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Those slits are way too big to interact with the waves, that's why the cats are hitting the walls. The slits have to be proportional to the De Broglie wavelength of the particle. For a 6 kg cat going at 500 m/s, the wavelength is about 2.2 * 10^^-37 meters.
It's actually easy to prove using the ideal gas law that the balls dropped a full .5 psi more than they should have given the weather conditions. Moreover, the Colts' football air pressure met the predicted range of pressure drop.
HOWEVER, it is very difficult to prove that the measuring protocol was scientific and that the pressure gages were properly used and calibrated.
(I don't have a particular bias, I just enjoy discussing the ideal gas law.)
That would be Gay-Lussac's law. The change in pressure of an ideal gas is proportional to the change in temperature of the system when both the mass and the volume remain constant.
1) I'll try to guide you through the process.
First of all you have the formula given and you already know the structure (an exception). You can use the formula to calculate the degree of unsaturation, ie. the number of double bonds or presence of rings in your structure.
With DBE = 4 and the fact that you only have 11 H for 8 C atoms, there must be an aromatic ring your structure, which will have 5 H atoms (monosubstituted benzene)
Calculator for DoU or Double Bond Equivalents (DBE)
If you don't have nitrogen or halogen in your compound, N and X will be 0. So C8H8O will have DBE = 5. Most likely a ring system, aromatic group and a C=O bond.
The numbers are crystallographic directions. The notation is called Miller Indices.
If you line up an x, y, z coordinate system with the edges of the unit cell of a crystal, you can think of them as vectors. In other words, the <112> direction is where you go one unit cell in the x direction, 1 in the y, and 2 in the z. The (112) plane would be the plane of atoms perpendicular to this direction.
The wikipedia page I linked has a nice description. The first picture is a bunch of examples of different planes in cubic crystals. As you can see, the (100) plane points in the same direction of the faces of the cube. The (110) plane points the same way as the edges. And finally, the (111) plane points in the direction of the corners. That is what I was trying to describe in the 3rd paragraph above.
If you input a 111 plane, then rotate the model so you are looking perpendicular to the plane, you will see that one of the corners of the cube will be pointed at the camera. Same thing with 100 planes and 110 planes except faces and edges will be pointed at the camera respectively.
First thing you need to do is calculate how many double bonds is in the molecule the Double Bond Equivalent (DBE). Remember that a ring also counts as a double bond. Ex. benzene would have a DBE of 4, three for the double bonds and 1 for the ring structure. With the information given by the IR spectra you can figure out what functional groups might be present in the molecule. Separate the groups given by the NMR analysis (3H means that that it is probably an CH3 group. The δ is the the chemical shift, the higher the δ, means that the Hydrogens are close to an electron rich group or is attached to one. You can use this table to help you figure out where they could be. In the NMR data you can also notice these letters ( s, d, t, q). Those are the splitting of the peak Singlet(1 peak) , Doublet(2 peaks) , Triplet(3 peaks) , Quartet(4 peaks). The amount of peak minus one tells you how many neighboring Hydrogen's you have. So a CH3-O-R group would show a (3H,s) peak, while the peak of the CH2 in CH3-CH2-O-R would show (2H,q) peaks because it has 3 neighboring hydrogens.
By the Nernst Equation, the overall cell potential should change, but the standard cell potential will not. Q (mass action expresion) appears in the Nernst equation, not Keq, which is a constant.
