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I was a little confused by your comment at first but figured it out. So if anyone was wondering, pretty much do Mathway.com/(insert other country domain here).
I tried it with the French version and it works. https://www.mathway.com/fr
This is a really great tip, dude you're a legend. Thanks a lot.
If 2+2 = it’s happening to the fifth power then it’s happening = 1.31950791. Thats 1319.50791% when converted to percentage. If you graph the fifth root of 4 you get this plot . Which you can clearly see is in the shape of an S moving from negative 10 to positive 10 in both the X and Y axis. The S is basically proof that he’s signed since that’s what it stands for and the negative 10 to positive 10 is his move from being the number 10 for juve ( his old career) to our number 10 ( a positive bright beautiful future). I can go deeper but do you guys really need more proof? The math checks out this is scientifically proven.
Pearl won 4 Splatfests in a row and has won 5 out of 6 so far. Using this calculator and entering 6*C5* (6 coin tosses with 5 being heads), we can see that the chances of this happening is of 6/64 or 3/32 or 9.375%. It's not that rare actually.
In every Splatfest the chances of winning are around 50% if the choices are similar, like Sci. Fi vs. Fantasy or Vampires vs. Werewolves, but they can be slightly slanted if one of the options is objectively inferior, such as Over vs. Under.
My suggestion? Choose what you wish. Super Sea Snails are not that important, and I think choosing what you like whether you win or lose is much better.
Combinatorial theory: 2(7 choose 3)
N! / r!(n-1)!
N is 7 because there are 7 games in the series, r is 3 because it's 4 is potentially the deciding game. Multiply it by 2 because it can be split so game 7 determines it.
7 choose 3 is 35. Multiply by 2 is 70 different variations.
standard deviation of contraptions: ~1.432 . Remember that here you want the population standard deviation, so replace the n-1 with n.
cumulative distribution function: 6/36 (0.166) chance for 0 or less 16/36 (0.444) chance for 1 or less 24/36 (0.222) chance for 2 or less 30/36 (0.833) chance for 3 or less 34/36 (0.944) chance for 4 or less 36/36 (1.000) chance for 5 or less
reverse-cumulative distribution function: 36/36 (1.000) chance for 0 or more 30/36 (0.833) chance for 1 or more 20/36 (0.611) chance for 2 or more 12/36 (0.388) chance for 3 or more 6 /36 (0.166) chance for 4 or more 2/36 (.055) chance for 5 or more
This may or may not help but I plugged your equation into here: https://www.mathway.com/Algebra
It brings up a list of things to solve for. Just go through them and see if it makes sense. At least put up an effort and try to get some partial showing that you tried everything regardless if you were wrong or not.
Nah, for this class u need mathway it has a specific stats calculator and breaks down every problem with the step by step solutions. This is what I used for all my math and science courses. It helped so much.
The multiplication there is only what the chances are of gladiators B, C, D, and E (or any four other specific gladiators) attacking.
What you would actually need is to take what are the chances that 4 gladiators do attack, and that 5 gladiators don't.
So the first step is .11^4 times .89^(n-5)
But this is just the probability that the first four gladiators attack, and the rest don't. In actuality, any combination of four gladiators would satisfy. So what you'd want to look at is how many ways can you select 4 gladiators from 9 possible gladiators, or more mathematically speaking, what is 9 choose 4?
https://www.mathway.com/popular-problems/Finite%20Math/600050
There's 126 ways, so it'll be the probability above multiplied by that.
Holy shit. You're me.
I'm sorry to make this about me, but I didn't pass high school math until my 2nd year in college.
I remember driving up a hill in my car, hadn't done ANY homework all semester, barely passed 2/3 tests, failed the other 1/3.
I remember I was about to give up, as I was driving home from class but, I distinctly remember driving up a hill and telling myself I wasn't going to give up, roll over and fail like always.
I sat my ass down for 2 days straight, did every piece of homework for the class, went in and took my final and got a 98/100. The professor was even floored.
Learn. Use YouTube, or shit like https://www.mathway.com/Algebra to reverse engineer problems.
Dude, just keep the positive attitude. I know it sounds like bullshit, but my GPA was below a 1 my 2nd semester of college, and I was able to make it into a 3.1 before I graduated.
When I was your age (early 30s now) I thought my life was going to be dog shit, but not to humble brag, but I just bought a house, a 20k car, and having a child Wednesday next week, and I can afford it all, because I doubled down on myself. You've got this shit. Don't give up dude.
I typed in both of the following formulae into this calculator:
e > or = 0
π > or = 0
and the results were "The inequality is always true." Is the computer playing tricks on me or are we radically redefining these constants?
Question: 6/2(1+2) Solution: 1
How? 1. (PEMDAS): 6/2*(1+2) -> 2+4 = 6 -> 6 / 6
= 1
Verified via: https://www.mathway.com/Algebra
Though I'm not sure if I'm right. Math Solver tried to do it the other way and output "9" as a solution.
6 / 2(1+2) -> 3(1+2) — Conflict with PEMDAS! -> 3*3 -> 9
I stand for "1", but if I'm wrong, correct me.
I STRUGGLED with math so much, I dropped out of college. I ended up going back and I got through it but it took all of me to get through this. I even got tested because I thought I had a learning disability, I didn't. Some people struggle like you and I. Tears, frustration, constant anxiety. I had to get a tutor and spent countless hours doing problems over and over again. You could have a teacher that doesn't work for you, it happened to me.
I don't know if you are in HS or college but if you struggle this much in match, make sure your other classes are easier disciplines. If you are in college, maybe just take that one class for the semester and really focus. YouTube is a great resource that will walk you through problems, type in the equation name and you will get hits on how similar problems are solved. Also try this tool. If you get stuck on a problem it will walk you through it step by step: https://www.mathway.com/Algebra
There's a really helpful website that helps you with (almost) every math question/problem.
https://www.mathway.com/
All you have to do is type in your problem and pick how you want it solved. It's helped me so much. It's cheating, but heck it's useful as hell if you're desperate.
All of them ask to put it into slope-intercept form.
This means the form y=mx+b.
You want to take the equations and turn them into a form where y is on one side and x is on the other side.
3x + 3y = 21
3y = 21-3x | Moved 3x to the right side
y = -x + 7 | Divided by 3
Now you put it into the graph.
In y = mx+b, b is the y-intercept, which is the point (0, b). Or the point on the y-axis. M is the slope, which is change in y / change in x.
So you will draw the point (0,7). Then the slope is -1. Or -1/1. So you draw the next point by going down 1, and right 1. (1, 6) or you can do up 1, left 1 (-1,8)
As for checking answers, you can use this to turn equations into slope-intercept.
https://www.mathway.com/Calculator/slope-y-intercept-calculator
You can use any online graphic calculator to get the graph.
Antes lo sabía.
Busqué en google y encontré este sitio que te resuelve todo: https://www.mathway.com/es/Algebra
Ahí ingresé la fórmula tuya y me tiró la gráfica y más datos relevantes, probala.
If you want one fraction, or you could solve for the other variables. It doesn't really get much simpler, though. I used Mathway, but there's a lot of calculators online for this kind of stuff, too, some of which show you steps. I can show work if needed, but it's just some basic algebraic manipulation.
https://www.mathway.com/Algebra
Enter the decimal number and hit convert to simplified fraction. Mathway is also an app. Then, just find that location on the tape measure. If you don’t know how to read a tape measure just look it up. If you need to convert cm to in or vice versa just google it
https://www.mathway.com/popular-problems/Precalculus/400999
The period of csc is 2pi divided by whatever multiplies the x (the coefficient of x).
csc(4x) period = 2pi/4 = .5pi.
E
Here is a link to mathway where they work this exact problem:
https://www.mathway.com/popular-problems/Calculus/542759
There will be three answers in your interval.
u/RepresentativeJump66 I do have Level M solution books however they are only the old version. Let me know if you would like to have those.
However, there is this link that can help you out in any math area such as Algebra, Calculus, Graphing, etc: https://www.mathway.com. This site also gives out step by step answer solutions. Hope this helps.
I don't have the solution book but you can send me a screenshot of the problem and I'll try to walk you through the problem.
Additionally, there is this link that can help you out in any math area such as Algebra, Calculus, Graphing, etc: https://www.mathway.com. This site also gives out step by step answer solutions if you make an account.
u/RepresentativeJump66 So sorry, unfortunately, I do not have level M solution book, and anyway I do not give out just ANSWERS.
However, there is this link that can help you out in any math area such as Algebra, Calculus, Graphing, etc: https://www.mathway.com. This site also gives out step by step answer solutions. Hope this helps.
https://www.mathway.com A coworker introduced it to me. This website also has an app and had been a lifesaver as a supplement for my math courses. It shows you step by step how to solve nearly any problem. It also can act as a graphing calculator.
Well the derivative would be 4/5x^1/5 , which at x=0 would be undefined, and yes, when looking at the graph, it appears to make an angle, not the same as |x|, its a bit different, if you want you could quickly look at it on Mathway , please do tell me if I made an error.
So you have the right probability for picking a brightly colored guppy in a single trial: 65%.
The first question is to find the odds of picking exactly 7 brightly colored when you randomly pick 10, one at a time, with replacement.
The odds of getting exactly 7/10 bright ones means you also picked exactly 3/10 drab ones. The odds of picking a drab one in a single trial are 35%.
To combine these odds, you multiply them together. The odds of getting 7 bright ones are 65%^7 = 0.65^7 = 0.049 = 4.9%. The odds of getting 3 drab ones are 35%^3 = 0.35^3 = .043 = 4.3%. The odds of getting 7 bright AND 3 drab are 4.9% x 4.3% = 0.0021 = 0.21%.
But be careful. This number represents the odds of getting 7 bright and 3 drab in one particular order. We now have to account for the fact that there are many orders in which you could make this selection. For example, B B B B B B B D D D is one order, and B B D B B D B B D B is another order.
How many different orders are there? To calculate this, there is a formula called 'choose'. The answer to the question "how many ways can I choose 7 from a set of 10?" is defined as the function '10 choose 7'. The answer is 120 (you can follow that link to find explanations of the formula -- it uses factorials).
Finally, we take the number of orders, 120, and multiply it by the odds of selecting (7 bright & 3 drab) in one particular order, 0.21%. The result is 120 * 0.21% = 0.252 = 25.2%.
Do you think you can take it from here?
If you’re terrible at math like I am this website will solve any kind of math problems for you. If you pay for a subscription (it’s cheap) it’ll even show you the steps on how to do it.
Mathway: https://www.mathway.com/
Rather than assuming what you’re trying to do with the equation, it asks what you want it to do whether it be simplifying, writing in a different form, factoring, etc., it will even ask how you want it done specifically. It’s amazing.
In the Portugal case, I thought about changing the formula that decide the strength of the opponents. right now it looks like this to something more like this (x=the opponents rank, y=the multiplier). So winning against teams like Sweden would give less points.
As to the punishing of top teams who fall against weaker ones, after i calculate the team's points, I divide it by the number of matches that the team has played, so if two teams played 6 matches, one won all 6, and the other lost 1 and won the rest, it should show in the total points. But I do agree that its not a hard enough of a punishment.
Although, if SK lost 4-0 to Switzerland and then went on to win the entire WC, should we really punish them for only one lost match? Even so, if a strong team losses to a very weak team, the strong team would probably loss the other stronger teams, and eventually it'll stack up and it'll show at the end.
I found a solution to the problem online and was able to follow along and did not understand the rest of the solution so I wanted clarification of the concepts/rules for exponents and square roots.
https://www.mathway.com/popular-problems/Pre-Algebra/173441
I divided both sides by 5 to get (x-2)^2 = 25
The next step Take the square root of each side of the equation to set up the solution for x
(x−2)^2⋅1/2=±√25
I do not understand why the square root is plus/minus and why the exponent is divided by 1/2. This is the part of the solution I did not understand and where I got lost.
Next step:
(x-2) = ±5
x = -5+2 = -3 OR x= +5+2 = 7
I use the default functions, such as downloads, history, and bookmarks. I am constantly downloading and trying out different software—I love open-source stuff and I am very curious. I don't use Vivaldi's notes very often simply because I would want them to sync if I did. I don't usually use the tree-tab view, but I guess I like having the option. I also added a web panel for Mathway because I find it easier to use when it is in an aspect ratio more similar to a mobile device in portrait mode.
On the third step (consolidation), I'm having trouble understanding where the 2x is coming from. In the second step, one side has -2x and the other has 6x.
Edit: Just realized that you meant 6y, not 6x on the right side. This means my error was -1x on the left side when it was supposed to be -2x. Could you explain or point me to a resource that explains this expansion? I thought (x-1)^2 would be x^2 - 1x + 1 and I'm still confused why it isn't.
Second edit:
I googled better and found this: https://www.mathway.com/popular-problems/Precalculus/402540
Basically I need to work on my FOIL!
Thank you for your answer!!
I'm not sure I follow. What I mean is the graph of a linear formula like y=x
https://www.mathway.com/popular-problems/Algebra/200126
Increases much more quickly than the graph of a logarithmic formula like y= log(x)
http://www.rapidtables.com/math/algebra/logarithm/logarithm-graph.htm
Therefore, if winning is indicated by having a greater value, it would behoove one to bring linear logic to a logarithmic party.
So I'm just guessing but for the first one, that looks like a discrete variable, as they are finite measurements. A continuous variable would have something like a height measurement, which can be an infinite variable, this means that a continuous variable can look like: 23.44345623424..... and go on forever. However a discrete variable is exact, such as the amount of fast food eaten per week, which could be 2 or 5 or 1. For the measures of central tendency, that is calculations such as the mean, median and mode. If you're looking at more advanced stuff you could be facing standard deviations and other such calculations. In this case the mean, median and mode are all appropriate. To calculate these measures, just look that up on google, they're pretty simple. As for meanings: MEAN: is the overall average (so the average amount of fast food eaten per week) MEDIAN: is the middle value, so you must arrange your values in ascending order (0-8) and then find the middle number (literally the number in the middle) so to find that middle number exactly (helps for large amounts of numbers) add up the number of numbers and divide that answer by two. If you get something like 14.5, then either round up, or include both the upper and lower number. MODE: is the value that occurs the most. So in this case it would be 0 and 3, as they both occur 3 times each.
For the second question's weird "cumulative frequencies" it looks like all you need to state is how many times that result occured, check this out. Looks like you just need to plot a stem and leaf chart or something like that.
Good luck!
This does a pretty good job of explaining this using sum/difference identity, but it'll also give away the answer so just use it responsibly I guess: https://www.mathway.com/popular-problems/Precalculus/412034
Honestly, if you're having trouble learning HOW to do math related stuff. This Website really helps, it'll give you step by step instructions on the how and why of things. Granted, people can use this site for other reasons than intended, but if you really need to learn it and are having trouble figuring out WHY things are happening, or HOW to go about solving a problem and you're just absolutely stumped, it's a very useful and helpful learning aid.
Back in the day, before I went to university after a few years in the workforce, I re-learned maths from decimals onwards by going to a really basic Fundamentals of Mathematics class at the local uni and supplementing that with many hours of online study. I didn't use Khan Academy or anything because working through videos is not as efficient as cutting your teeth on some real problems.
Anyway, I used Mathway a lot. It can generate worksheets of questions and there are many other websites that offer pre-made worksheets if you just google for them. The most important and useful feature of Mathway, though, was that I could feed it an equation and it would solve the thing step-by-step and explain the logic at each step. That's a paid feature, if I remember right, but it was so worth it for the months that I needed it.
I find Mathway's solver one of the best tools for any student that exists. Not much can be said about it, other than it can do almost anything. Highly recommend anyone to check it out.
Is this your equation? http://i.imgur.com/HuYaQA3.png
If so, I think there isn't a verification for this equation. The equation is false, I think.
If this is not your equation then please rewrite the equation, or use this site (https://www.mathway.com/) and write the equation out and screen capture it. I request the screen capture, or a picture of the equation as I think there is a miscommunication here.
Mathway Solve your math problems.
~~Just a question, is it possible to ask you for all 3 RPG Maker DLC?~~
I will take The Book of Unwritten Tales Digital Deluxe Edition instead. I don't own base game of RPG Maker ^^
A girl turned me on (hehe) to Mathway today for algebra, and it is fucking awesome. I think you have to subscribe to see how to get the answer, but if you're just running through a bunch of old online assignments it's pretty great.